Electric Field

What is test charge and why it is made neglibile small while testing the effect of the source charge?

What are the significance of electrical field lines?

A small metal ball is suspended in an uniform electric field with the help of an insulated thread. If a high energy $\mathrm{X}$-ray beam falls on the ball, then the ball

An electrostatic field line leaves at an angle $\alpha$ from point charge $q_1$ and connects with point charge $-q_2$ at an angle $\beta$($q_1$and $q_2$ are positive) see figure below. If $q_2=\frac{3}{2}{q}_1$ and $\alpha =30°,$ then

Two masses $M_1$ and $M_2$ carry positive charges $Q_1$ and $Q_2,$ respectively. They are dropped to the floor in a laboratory set up from the same height, where there is a constant electric field vertically upwards. $M_1$ hits the floor before $M_2$. Then,

Two fixed point charges $+4q$ and $+q$ units are separated by a distance of $a$. The distance, where the resultant electric field intensity is zero, measured from charge $+4q$ is

The change in force experienced by a static charge due to an accelerated charge is not instantaneous. Explain.

Which one of the following statement is not correct about electric field?

A small sphere of mass $2\mathrm{ g}$ having charge $5\mathrm{ }\mathrm{\mu C}$ is suspended using an insulated string as given in figure. Find the angle made by string with vertical if it is placed in electric field of magnitude $2000$ $\mathrm{V} {\mathrm{m}}^{-1}$ towards right

A vanishingly small point charge $q$ experiences a force $\overrightarrow{F}$ due to a source charge present in space. The ratio $\frac{\overrightarrow{F}}{q}$ is:

A much higher value of a test charge does not affect:

In order to find the electric field due to a point charge in space, the test charge should be negligibly small? Explain with reason.

What do you mean by a test charge?

How we can determine the electric field due to continuous distribution of charge?

In the figure, four point charges are placed at the four corners of a square of side $2 \mathrm{cm}$. Determine the magnitude and direction of electric field at the centre $\mathrm{O}$ of the square $Q=0.02 \mathrm{\mu C}$.

Equal charges $q$ each, are placed at the vertices $A$ and $B$ of an equilateral triangle. Find the magnitude of the electric field at the vertex $C$.

What is the net force on an electric dipole in a uniform electric field?

What is the magnitude of the intensity of electric field that can balance the weight of an electron? Given, $\mathrm{e}=1.6\times {10}^{–19}\mathrm{C}, \mathrm{g} = 9.8 \mathrm{m}/{\mathrm{s}}^2 \& {\mathrm{m}}_{\mathrm{e}}=9.1\times {10}^{-31}\mathrm{kg}$.

Two point charges $+9\mathrm{e}$ and $+\mathrm{e}$ are at a separation of $16 \mathrm{cm}$. Where another charge$q$ must be put on the line joining two charges such that it remains in equilibrium?